# SOLUTION: I REALLY NEED THE ANSWER IN DETAIL TO THIS PROBLEM..ITS DUE TOMORROW and its very important. THANK YOU * A window in a bulinging is 18m above the ground. From this window, the an

Algebra ->  -> SOLUTION: I REALLY NEED THE ANSWER IN DETAIL TO THIS PROBLEM..ITS DUE TOMORROW and its very important. THANK YOU * A window in a bulinging is 18m above the ground. From this window, the an      Log On

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 Question 24850: I REALLY NEED THE ANSWER IN DETAIL TO THIS PROBLEM..ITS DUE TOMORROW and its very important. THANK YOU * A window in a bulinging is 18m above the ground. From this window, the angle of elevation to the top of the building across the street is 40° and the angle of depression to the bottom of the building acress the street is 42°. How tall is the building across the street? Include a labelled diagram with you solution.Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!* A window in a bulinging is 18m above the ground. From this window, the angle of elevation to the top of the building across the street is 40° and the angle of depression to the bottom of the building acress the street is 42°. How tall is the building across the street? Include a labelled diagram with you solution I AM GIVING A GRAPH BELOW FOR YOUR GUIDANCE.YOU CAN COMPLETE THE DRAWING AND LABEL THE DIAGRAM ON THE BASIS GIVEN BELOW. LET O BE THE ORIGIN;LET THE Y AXIS BE THE BUILDING , THE WINDOW AT 18M.ABOVE GROUND BE ON THE Y AXIS AT W ; AND X AXIS THE GROUND. HENCE OW = 18 M. THE LINE OF ELEVATION OF TOP OF THE BUILDIND ACROSS THE STREET FROM WINDOW ON Y AXIS IS SHOWN BY WT;AND THE LINE OF DEPRESSION OF THE BUILDING FROM THIS WINDOW IS SHOWN BY WB.JOIN BT WHICH WILL BE PERPENDICULAR TO THE GROUND OR X AXIS.DRAW A HORIZONTAL W H FROM WIDOW W TO BUILDING LINE BT. WE HAVE 2 RIGHT ANGLE TRIANGLES WTH AND WHB.IN TRIANGLE WTH ANGLE TWH = 40 DEGREES THE ANGLE OF ELEVATION HENCE TAN 40 = TH/WH OR TH =WH * TAN 40.............I IN TRIANGLE WHB ANGLE HWB = 42 DEGREES THE ANGLE OF DEPRESSION. HENCE TAN 42 = HB/WH OR WH=HB/TAN 42 BUT HB = OW =18 M ..SO..WH=18 /TAN 42.................II SUBSTITUTING IN EQN.I WE GET TH = 18*TAN 40 / TAN 42 SO HEIGHT OF BUILDING = TH +HB =18*TAN 40 / TAN 42 +18 =18*{(TAN 40 / TAN 42 ) + 1 }..YOU CAN SUBSTITUTE THE VALUES FOR TAN 40 AN TAN 42 AND GET THE HEIGHT AS 34.77 M.