# SOLUTION: find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function f(x)=1/2(x+6)^2+3

Algebra ->  -> SOLUTION: find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function f(x)=1/2(x+6)^2+3      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Mathway solves algebra homework problems with step-by-step help!

 Click here to see ALL problems on Quadratic Equations Question 236217: find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function f(x)=1/2(x+6)^2+3Found 2 solutions by stanbon, Edwin McCravy:Answer by stanbon(60771)   (Show Source): You can put this solution on YOUR website!find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function f(x)=1/2(x+6)^2+3 ------------------ Vertex (-6,3) Line of symmetry: x = -6 Minimum at the vertex is f(x)=3 ----------------------- ===================================================== Cheers, Stan H. Answer by Edwin McCravy(9716)   (Show Source): You can put this solution on YOUR website!``` The equation is a parabola with a vertex at (h,k) and which passes through the points (h+1,k+a) and (h-1,k+a), and its axis of symmetry is the vertical line whose equation is So in the problem: , , [Notice that the sign is changed for h but kept for k] So the vertex is (h,k) or (-6,3), The parabola passes through (h-1,k+a) and (h+1,k+a), or (-6-1,3+) or (-7,) and (-6+1,3+) or (-5,) Its axis of symmetry is the vertical line whose equation is or We plot the vertex (-6,3) We draw the axis of symmetry which is a vertical line through the vertex (the green line below: Then we plot the two points, one on each side of the vertex (-7,) and (-5,) Finally we sketch in the parabola: Edwin```