# SOLUTION: I don't understand these Please help Thanks, Solve by completing the square 1. x^2 - 6x = 16 I get (6/2)^2 = 9/4 = (x-9/4)^2 then I am lost. 2. 2x^2 - 3x + 1 = 0 I get a

Algebra ->  -> SOLUTION: I don't understand these Please help Thanks, Solve by completing the square 1. x^2 - 6x = 16 I get (6/2)^2 = 9/4 = (x-9/4)^2 then I am lost. 2. 2x^2 - 3x + 1 = 0 I get a      Log On

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 Question 203051This question is from textbook : I don't understand these Please help Thanks, Solve by completing the square 1. x^2 - 6x = 16 I get (6/2)^2 = 9/4 = (x-9/4)^2 then I am lost. 2. 2x^2 - 3x + 1 = 0 I get as far as 2^2 - 3x =1 x^2 3/2 = 1/2 x^2 9/4 = 1/2 Now I am lost 3. x^2 - x - 1 = 0 Is this just {1,-1} This question is from textbook Answer by KY(1)   (Show Source): You can put this solution on YOUR website!X^2 - 6X = 16 Complete the square in the left X^2 - 6X + 9 - 9 = 16 (X-3)^2 - 9 = 16 (X-3)^2 = 25 (X-3)^2 = 5^2 so X-3 = 5 ===> X = 8 or X-3 = -5 ===> X = -2 Answer : X = -2 or 8