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Tutors Answer Your Questions about Quadratic-relations-and-conic-sections (FREE)
Question 66711This question is from textbook 
: I have no idea how to do anything with conics, our teacher is not the best teacher and my question is, how to write an equation for the conic section- Ellipse with vertices at (-2,2) and (4,2) and co-vertices at (1,1) and (1,3)This question is from textbook
Click here to see answer by Nate(3495)   |
Question 67368: Question 1 (10 points)
Find the distance between the two points (3,-4) and (-4,5)
Question 2 (10 points)
The idea of eccentricity is associated to which one of the four types of conic sections?
Question 3 (5 points)
Each of the next four questions refer to the parabola y = 5(x+2)^2 + 7.
Find the vertex of the parabola
Question 4 (5 points)
Find the focus of the parabola
Question 5 (5 points)
The directrix line of the parabola is the line y =
Question 6 (5 points)
The length of the latus rectum of this parabola is
Question 7 (20 points)
Find the standard form of the circle x^2 + y^2 + 2x - 6y - 6 = 0.
Question 8 (5 points)
For the circle x^2 + y^2 + 2x - 6y - 6 = 0 of the previous problem, find the center.
Question 9 (5 points)
For the same circle x^2 + y^2 + 2x - 6y - 6 = 0 of the previous two questions, find the radius.
Question 10 (20 points)
Find the standard form of the ellipse given by the equation x^2 + 25y^2 -2x + 150y + 201 = 0.
Question 11 (5 points)
Here is the equation of an ellipse in standard form: (1/16)(x + 2)^2 + (1/9)(y - 5)^2 = 1 . Each of the next four questions refer to this ellipse. Find the center of the ellipse.
Question 12 (5 points)
Find the foci of the ellipse.
Question 13 (5 points)
Find the length of the major axis.
Question 14 (5 points)
Find the distance between the two foci.
Question 15 (20 points)
Find the standard form of the hyperbola given by the equation 4x2 – 25y2 – 50y – 125 = 0.
Question 16 (5 points)
Here is the equation of a hyperbola in standard form: (1/10)(x - 1)^2 - (y - 1)2 = 1 . Each of the next four questions refer to this hyperbola. Find the center of the hyperbola.
Question 17 (5 points)
Find the foci of the hyperbola.
Question 18 (5 points)
One of the two axes (transverse or conjugate) is parallel to the y-axis. Find its length.
Question 19 (5 points)
Find the two asymptotes for the hyperbola
Click here to see answer by checkley71(8405) |
Question 68611: I need to know how to solve this: 
I need also:
Type of Conic__________
Standard Form__________
Center/Vertex__________
Direction __________
and How to Graph It
PLEASE help I have a test soon.
Click here to see answer by Nate(3495) |
Question 70091: Find the center,foci,and vertices of the ellipse and determine the lenghts of the major and minor axis. Then sketch the graph.
(x+2)^2/4+y^2=1 I thought both numbers in the equation needed a denominator. I put a 1 under the y^2. Is this correct?
The center: (2,0)
a^2=4 so a=+or-2
Vertices: (-2,0+or-2)-->(-2,2),(-2,-2)
Major Axis: 2a=2*2=4
Minor Axis: 2b=1
b^2=1-->b=+or-1
Foci: (-4,0) (0,0)
Is this correct? I don't have a problem with the sketching. I just do not understand how to do it without the denominator under y^2.
Click here to see answer by stanbon(26283) |
Question 70324: My son is in 10th grade, taking Algebra II. They just started this new section last week when my son was out sick two days. He is struggling with understanding his make-up work and won't be able to see the teacher until Tuesday after school. I hope you can help me help him in the meantime?
I'm not sure how to symbolize square root in your system either?
I'll use "sq rt" for square root -- ok?
Here is what he's done so so far, squaring, simplifying and getting the GCF
(5 times sq rt of 3 + 3 times sq rt of 5)(squared)
work:
(25x9) + 30 times sq rt of 15 + (9x5)
answer:
270 + 30 times sq rt of 15
Is that anywhere near correct?
Thank you so much!
Click here to see answer by stanbon(26283) |
Question 70615: ah help meeeeeee :[[ it says determine whether each parabola opens upward,downward,left or right.
1) y=-6x[squared]
2) 2x+6y[squared]=0
THEN, it says identify the focus and the directix of the graph of each equation
:(
y=-8x[squared]
x-5y[squared]0
thanks guys :(
Click here to see answer by stanbon(26283) |
Question 70893: AH peoplle please help im stuck on these!!
ahh
:(
it says Determine an equation of the parabola with the following property
1) Focus at (0,-6) and directrix y=6.
THEN it says
determine the vertex,focus,and directrix for each parabola. Sketch each parabola.
1) y[squared]=-3x
2)x[squared]=12y
3) x[squared]-8x-y+20=0
oh man please help anyone! :(
Click here to see answer by stanbon(26283) |
Question 72735: I keep finding examples that have the problem squared but none without. I would appreciate any and all help with this.
Find the vertex of y=-2(x -3) + 4 and then graph.
I think the vertex is (6,4) and the -2 makes it open downward if im correct. I came up with (5,0) and (-1,0) as the x intercepts and (0,10) as the y intercept. When I plot them on a graph with the vertex, the points are all over the graph so Im doing something wrong. Please please help!
Click here to see answer by stanbon(26283) |
Question 74051: please help explain this equation:
find the vertex, focus, axis, directrix and latus rectum of the parabola
x^2+y=6x-14.
i found the vertex to = (3, -5)
i am not sure how to find the rest..thanks for any help.
this is from a problem we were given in class
Click here to see answer by checkley75(3666) |
Question 74533This question is from textbook Algebra 2
: Hi! I just submitted this problem, but I think I figured it out! Can someone tell me if this is correct?
Write an equation for an ellipse if the endpoints of the major axis are at (1,6) and (1,-6) and the endpoints of the minor axis are at (5,0) and (-3,0).
The length of the major axis would be 12 units. 2a=12. a=6.
The length of the minor axis is 8 units. 2b=8. b=4.
The equation for an ellipse is y^2/a^2 + x^2/b^2=1.
So the answer would be y^2/36 + x^2/16=1.
Can someone please tell me if I did this right?This question is from textbook Algebra 2
Click here to see answer by stanbon(26283) |
Question 74533This question is from textbook Algebra 2
: Hi! I just submitted this problem, but I think I figured it out! Can someone tell me if this is correct?
Write an equation for an ellipse if the endpoints of the major axis are at (1,6) and (1,-6) and the endpoints of the minor axis are at (5,0) and (-3,0).
The length of the major axis would be 12 units. 2a=12. a=6.
The length of the minor axis is 8 units. 2b=8. b=4.
The equation for an ellipse is y^2/a^2 + x^2/b^2=1.
So the answer would be y^2/36 + x^2/16=1.
Can someone please tell me if I did this right?This question is from textbook Algebra 2
Click here to see answer by funmath(2873) |
Question 74529This question is from textbook Algebra 2
: Hi! Can someone please help me with this problem?
Write an equation for an ellipse if the points of the major axis are at (1,6) and (1,-6) and the endpoints of the minor axis are at (5,0) and (-3,0).
Thanks!This question is from textbook Algebra 2
Click here to see answer by funmath(2873) |
Question 74446This question is from textbook Algebra 2
: Write an equation for an ellipse if the endpoints of the major axis are at (1,6) and (1,-6) and the endpoints of the minor axis are at (5,0) and (-3,0).
My book doesn't show me how to write the equation with the major and minor axis points. Can someone help me? Thanks!This question is from textbook Algebra 2
Click here to see answer by scott8148(3382)  |
Question 74598: anybody good at parabolas?
on my "Y" axis from 1 through 5 the top of the parbola (known as V(-3,4)) is at 4 where it begins its downward peak.
on the "X" axis the right leg comes through -1 curves through the "Y" axis of 4 and the left leg goes back down through -5 on the "x" axis.
Question: Determine the standard equation of the parabola.
I know you people are whizzes and I would really be impressed. I have missed every question concering parabolas.
Thank you
Click here to see answer by stanbon(26283) |
Question 74667: i am having trouble understanding these types of questions..can you help?
length of the major axis of the ellipse 3x^2+2y^2=6 is __________?
this is a problem we had in our class to be reviewed tomorrow..thanks.
Click here to see answer by stanbon(26283) |
Question 74682: sketch a graph of the following (find and include focal points, verticies, asymptotes, directrix, as appropriate). Estimate any irrational values on the graph.
1. y = 2x^2 - 10x + 27
first i tried to get all of the x and y's to one side, then complete the square, but i didn't know how because y in this problem is not squared...but i tried it anyway and got... 27/4 (y-27)= x^2 - 5x + 25/4 ...i'm not sure where to go from here>???
Click here to see answer by stanbon(26283) |
Question 73350: The pool at a park is circular. You want to find the equation of the circle that is the boundary at the pool. Find the equation if the area of the pool is 900 square feet and (0,0) represents the center of the pool. Use EXACT values only.
I thought my answer was right, but it's not; what did I do wrong + what is the correct answer?
x^2 + y^2 = 286.4788976
Click here to see answer by jim_thompson5910(13794) |
Question 74846: i am working on hyperbola's and im not sure if i am understanding it yet. could see if i got the right answer to this one? thanks for any help. this is from a problem we had in class.
The center of the hyperbola 9x^2-16y^2-18x+32y-151=0
the answer i got was (1,1)
Click here to see answer by Nate(3495) |
Question 74847: could you help me with this equation? it is from a question we had in class.
The focus of (x-1)^2 = (y-2) is_____.
i said the answer is (-2,-1)
can you tell me if i got it right? thanks for any help.
Click here to see answer by Nate(3495) |
Question 74845: i am working on hyperbola's and im not sure if i am understanding it yet. could see if i got the right answer to this one? thanks for any help. this is from a problem we had in class.
The center of the hyperbola 9x^2-16y^2-18x+32y-151=0
the answer i got was (1,1)
Click here to see answer by venugopalramana(3286)  |
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