|
Tutors Answer Your Questions about Quadratic-relations-and-conic-sections (FREE)
Question 56426: Hope you can help me
"What degenerate form or forms of the parabola cannot be obtained from the intersection of a plane and a double napped cone? Describe how to obtain this (or these). Use a diagram to support your answer."
Thanks in advanced
Click here to see answer by stanbon(26297)   |
Question 57244: 1. A ball follows a flight given by y = 20x - x^2 + 6 where x represents the horizontal distance traveled in feet and y represents the height of the ball in feet. What will be the maximum height of this ball if it is thrown?
2. If x=2, x=-3 and x=0 are zeros of a polynomial, what is a possible equation for this polynomial?
3. What is the vertex of the graph given by
y=2x^2 - 4x + 3? Would the graph be a shift of y=2x^2?
4. Write the equation of the parabola given by y=2x^2-4x+3 in "standard" form.
Thank you very much!!
Click here to see answer by ankor@dixie-net.com(6693)  |
Question 58609: I needed to find the vertex of this parabola: y = -x^2 - 3x - 2
so what I did was:
0 = -x^2 - 3x - 2
x = -1, x = -2
Two x-intercepts: (-1, 0) and (-2, 0)
y = -0^2 - 3(0) - 2 = -2
One y-intercept: (0, -2)
x = 1/2(-1 - 2) = -3/2
y = -3/2
y = -3/2 - 2)-3/2) - 2 = 1.5
Vertex is -3/2, 1.5
Is this correct?
Click here to see answer by funmath(2873) |
Question 49056: I am not sure how to go about changing the following problem into standard form. I tried to do completing the square, but I'm not sure how to use it in this situation or when there is a coefficient other than 1 in front of x^2 and y^2. I would greatly appreciate help on how to solve the following problem. Thanks!
Change the equation to standard form and name the figure.
3x^2-2y^2-12x-20y-44=0
Click here to see answer by xerxes0212(2) |
Question 60403: Find the vertex and intercepts for each parabola. Sketch the graph
44. g(x) = x^2 + x – 6
i do not know if this question goes here or not because i do not know how to solve it or what to do. thanks for any help
Click here to see answer by funmath(2873) |
Question 62309: need help on this one please
complete the square and write the given equation in the standard form for the equation of a circle. then give the center and redius of the circle and sketch a graph
x^2 + 8x + y^2 + 4y + 16= 0
Click here to see answer by funmath(2873) |
Question 63653This question is from textbook 
: Hello, I'm Alex. Could I please ask your assistance on these two Homeschool American School Problems because I don't have a teacher here to help?
(1) What is the equation of the perpendicular bisector of the line between points (2,2) and (6, 6)?
(2) What is the (a)directrix and the (b)focus of the parabola y = x^2 - 5x + 4?
This question is from textbook
Click here to see answer by venugopalramana(3286)  |
Question 63873: Please help me find the soultion of this word problem :
Erica has a difficult golf shot to make. Her ball is 120m from the hole. She wants the ball to land 10m in front of the hole, so it can roll to the hole. A 15m tree is two thirds the way between her ball and the hole.
a) Choose the base of the tree as the origin, write an algebraic equation to model the height of the ball to just clear the top of th tree, in 1) factored form 2) vertex form.
Click here to see answer by stanbon(26297) |
Question 64382: please help me find the vertex, axis of symm., x and y intercepts, focus and directrix. It would be helpful if you could sketch the graphs showing the points.
y=-1/4(x-2)^2+4 and
x=3(y+1)^2-2
Thank you.
Click here to see answer by stanbon(26297) |
Question 64838: Please tell me if I am on the right track. I am to sketch the graph and id the foci of: 9(x-1)^2+4(y+3)^2=36. I came up with foci (1,-3+sqrt5) and (1,-3-sqrt5). Which is (1,-.764) and (1,-5.236).
Then I am to find the center of x^2+y^2=12x-12y. I came up with the center at (6,-6)with radius sqrt72. How did I do?
Click here to see answer by funmath(2873) |
Question 65049: I am having trouble using the point slope formula to find the equations of the asymptotes of ((x+3)^2/16)-((y+2)^2/25)=1. I know the slope is +or-5/4. I'm just not sure where to go from there. I also need some help finding the equation of the hyperbola described as having the foci at (5,0) and (0,-5) and the y-int. at (0,4) and (0,-4). Thank you very much.
Click here to see answer by cristiana(10) |
Question 65149: The distance between the points (1,3) and (-2,7) is:
25 units
units
7 units
5 units
Each of the remaining questions refer to the parabola y = 2x 2 + 12x + 17
The vertex of the parabola is:
(3,1)
(3,-1)
(-1,3)
(-3, -1)
The focus of the parabola is:
(3, -9/8)
(-3, -9/8)
(-3, -7/8)
(3, -7/8)
The directrix of the parabola is:
The vertical line x = -9/8
The horizontal line y = -9/8
The horizontal line y = 9/8
The horizontal line y = -7/8
The length of the latus rectum of the parabola is:
17 units
1/8 unit
2 units
1/2 unit
Click here to see answer by stanbon(26297) |
Question 65288: If the eccentricity of an ellipse (in other words, the value e) is close to zero, then the ellipse looks almost like a circle.
True
False
Each of the remaining questions refer to the ellipse 4x^ 2 + 9y ^2 - 8x + 36y + 4 = 0.
The center of the ellipse is at the point
(-1,2)
(-2,1)
(1,-2)
(2,-1)
The foci of the ellipse are the points
The length of the major axis of the ellipse is
6 units
3 units
4 units
2 units
The length of the minor axis is
3 units
6 units
4 units
2 units
Click here to see answer by Earlsdon(4900) |
Question 65287: The graph of a circle describes y as a function of x.
True
False
Which of these equations describes a circle with radius 5 and center (3,-2) ? (x - 3) ^2 + (y + 2)^ 2 = 25
(x - 3) ^2 + (y + 2)^ 2 = 5
(x + 3) ^2 + (y - 2) ^2 = 25
(x + 3) ^2 - (y + 2) ^2 = 25
Which of these equations describes a circle with radius 3/2 and center (0,4) ? x^ 2 - (y - 4) 2 = 9/4
x^ 2 + (y - 4) 2 = 3/2
(x - 4) ^2 + y 2 = 9/4
x^ 2 + (y - 4) 2 = 9/4
The circle whose equation is x^ 2 + 2x + y ^2 + 6y + 6 = 0 h
as center (1,3) and radius 2
has center (-1, -3) and radius 2
has center (-1, -3) and radius 4
has center (1, 3) and radius 4
The circle whose equation is x^ 2 - 6x + y ^2 + 2y = -4
Click here to see answer by Edwin McCravy(2922) |
Question 65743: A hyperbola is the only one of the conic sections whose graph contains two separate curves.
True
False
Each of the remaining questions refer to the hyperbola 36x 2 - 100y 2 - 72x + 400y = 3964.
The center of the hyperbola is
(2,1)
(1,2)
(-1,2)
(1,-2)
The foci of the hyperbola are at the points
(10.662, 2) and (-12.662, 2)
(-10.662, -2) and (12.662, -2)
(-10.662, 2) and (12.662, 2)
(2, -10.662) and (2, 12.662)
The length of the transverse axis is
5 units
10 units
20 units
none of the above
The equations of the two asymptotes are
y = (3/5)x + 7/5 and
y = (-3/5)x + 13/5
y = (-3/5)x + 7/5 and
y = (3/5)x + 13/5
y = (5/3)x + 7/5 and
y = (-5/3)x + 13/5
y = (3/5)x + 5/7 and
y = (-3/5)x + 5/13
Click here to see answer by venugopalramana(3286) |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395
|
| |
