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Tutors Answer Your Questions about Quadratic-relations-and-conic-sections (FREE)
Question 38739: When looking at an equation of a hyperbola in general form, how do you tell the difference between a hyperbola that opens up and down (y^2-x^2=1) and a hyperbola that opens left and right (x^2-y^2=1) without writing the equation in standard form? I know AC<0
Click here to see answer by Nate(3495)   |
Question 39217: Write the equation of a hyperbola from the given information. Graph the equation. Place the center of the hyperbola at the orgin of the coordinate plane. One focus is located at (0,6); one vertex at (0,-(square root) 7
Click here to see answer by Nate(3495) |
Question 39221: Identify the conic section represented by the equation by writing the equation in standard form. For a parabola, give the vertex. For a circle, give the center and the radius. For an ellipse or hyperbola, give the center and the foci. Sketch the graph.
16x^2+96x-9y^2+36y=36
Click here to see answer by venugopalramana(3286)  |
Question 36994: I am trying to come up with an equation for a parabola and I cannot seem to figure it out. I have an algebra 2 project where I have to write a paper on a problem that relates to my life. I want to find out the parabola of a corner kick in soccer. The corner is 25 yards away from the player the ball is being kicked to. The player is 5 foot 6 inches tall. I want the ball to be kicked from the corner to the players head. How could I write an equation for that?
Click here to see answer by venugopalramana(3286) |
Question 39732: I tried to solve this problem but I am not sure about my answer. The thing is, I solved it by following the examples given by the book but I don;t really understand the principle behind.
Find the vertex,focus and directrix of the parabola in the given equation:
3x + ysquare + 8y + 4 =0
y square -8y = -3x + 4
2(y square -4y +8 ) = -3x + 4 + 8
2(y square - 2) square = -3 (x + 4)
( y - 2) square = - 3/2 ( x + 4)
Vertex = 2, -4
4p= -3/2
p= - 3/8
Focus -4 + (3/8), 2 = 35/8, 2
directrix = X = -4 - (-3/8) = - 29/8
Click here to see answer by fractalier(1804)  |
Question 40296: a hyperbolic mirror can be usedto take panoramic photographs. A camera is pointed toward the vertex of the mirror and is positioned so that the lens is at one focus of the mirror. An equation for the cross section of the mirror is x squared/ 25 minus y squared/ 9 = 1 , where x and y are measured in inches. If you place a camera with lens at the focus, how far is the lens from the vertex of the mirror?
Click here to see answer by stanbon(26291) |
Question 40295: A comet follows a hyperbolic path about the focus of the Sun. The equation of the orbit is x squared/80 squared minus y squared/ 150 squared = 1, where x and y are measured in Gm. how far from the center of the hyperbola is the Sun.
Click here to see answer by stanbon(26291) |
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