# Questions on Algebra: Conic sections - ellipse, parabola, hyperbola answered by real tutors!

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 Algebra: Conic sections - ellipse, parabola, hyperbola Solvers Lessons Answers archive Quiz In Depth

 Question 385429: this is from the shifted conics sections, you have to identify whether it is a parabola, ellipse or hyperbola, and solve and graph the problem: 2x^2 + y^2 = 2y + 1 Click here to see answer by Edwin McCravy(8909)

 Question 385710: what would be the vertices, foci, and asymptotes of x^2/9-y^2/36=1 Click here to see answer by robertb(4012)

 Question 385902: What is the focus of the given parabola x^2+4y-4=0 Click here to see answer by robertb(4012)

 Question 386103: Find the vertices, foci, and minor axis: (x-1)^2/21 + (y-3)^2/4 = 1 Click here to see answer by ewatrrr(10682)
 Question 386103: Find the vertices, foci, and minor axis: (x-1)^2/21 + (y-3)^2/4 = 1 Click here to see answer by Edwin McCravy(8909)

 Question 386132: Graph the equation 2x^2 + 2y^2 -16x + 4y - 38 = 0 Click here to see answer by ewatrrr(10682)
 Question 386132: Graph the equation 2x^2 + 2y^2 -16x + 4y - 38 = 0 Click here to see answer by solver91311(16885)
 Question 386132: Graph the equation 2x^2 + 2y^2 -16x + 4y - 38 = 0 Click here to see answer by jsmallt9(3296)

 Question 386220: What do I do if there is a number before the y for a parabola. for example: 3y=(x-5)^2-6. I do not know what to do with the 3 Click here to see answer by tara0066(31)

 Question 386292: Find the midpoint M of the segment with endpoints (−7, −6) and (9, −8). Click here to see answer by rfer(12660)

 Question 386560: The equation below is a circle. What is the x-coordinate of the center of the circle? (x - 6)2 + (y + 5)2 = 152 Click here to see answer by ewatrrr(10682)

 Question 386992: Explain how to find the distance from the focus to the directrix of the parabola x=2y^2. Note: y^2 is y squared Click here to see answer by ewatrrr(10682)

 Question 387929: I am trying to find the y-intercepts of all I have been able to figure out is that the vertex is (-2,-1), if you could also show me how it is done that would be great. Thank you. Click here to see answer by stanbon(57347)
 Question 387929: I am trying to find the y-intercepts of all I have been able to figure out is that the vertex is (-2,-1), if you could also show me how it is done that would be great. Thank you. Click here to see answer by ewatrrr(10682)

 Question 387953: I am trying to find the y-intercept, as an ordered pair, of the equation . I have tried solving it myself by making "x" equal to 0 and then I simplified the equation to , and I was unsure as to what to do after that, or if that was even right. Thank you, and if there was any way that you could show me the steps you took that would be great. Thanks again. Click here to see answer by nerdybill(6959)
 Question 387953: I am trying to find the y-intercept, as an ordered pair, of the equation . I have tried solving it myself by making "x" equal to 0 and then I simplified the equation to , and I was unsure as to what to do after that, or if that was even right. Thank you, and if there was any way that you could show me the steps you took that would be great. Thanks again. Click here to see answer by 533908(1)

 Question 388126: y=1/3x^2-2x+7 I need to find the vertex. I know I first use the axis of symmetry which is x=-b/2a. I did that and I got 2/2/3. I don't know what to do next. Please help. Thank you. Click here to see answer by Theo(3464)

 Question 388163: x=5y^2+40y+77 Find the vertex. So far I used (b/2)^2=(40/2)^2=20^2=400 Then x=(5y^2+40y+400)-400+77 Then x=5(y^2+8y+80)-323 I don't know what to do afterwards. Click here to see answer by Fombitz(13828)

 Question 388449: Graph the parabola y=(x+1)^2-1 I found the vertex to be (-1,-1) axis is -1 and a=1 But I don't remember how to find the points. Click here to see answer by Fombitz(13828)
 Question 388449: Graph the parabola y=(x+1)^2-1 I found the vertex to be (-1,-1) axis is -1 and a=1 But I don't remember how to find the points. Click here to see answer by stanbon(57347)

 Question 388476: Graph the parabola: Y=(x+1)^2-1 To graph the parabola, plot the vertex and four additional points, two on each side of the vertex, and then click on the graph icon. It says I need 5 Points I have the vertex as (-1,-1) and two other points of (-2,0) and (0,0) I can't figure the other two points any help would be greatly appreciated. Click here to see answer by nerdybill(6959)

 Question 388496: Find the x-intercepts for the parabola defined by this equation: y=2x^2+4x-6. Click here to see answer by Fombitz(13828)

 Question 388545: Graph y=-5/8x^3 To graph the equation, first plot 5 points on the graph: one point with x=0 , two points with negative x-values, and two points with positive x-values. Click here to see answer by Alan3354(30993)

 Question 389054: On x-intercept for a parabola is at a point of (1.25,0).Fins the other x-intercept for the parabola defined by this equation: y = 4x^2-9x+5 Click here to see answer by Fombitz(13828)

 Question 389077: What are the solutions for the system of equations for x^2+y^2=36 y=x+2. I tried using substitution, but when it came down to the factoring part I got stuck. Click here to see answer by Fombitz(13828)

 Question 389086: The area of a rectangle is 48 square meters. The length of a diagonal is ten meters. Find the perimeter of the rectangle. Click here to see answer by richard1234(5390)

 Question 389241: one x-intercept for a parabola is at the point (0.6,0)use the quadratic formula to find the other x-intercept for the parabola defined by the equation: y=-5x^2+8x-3. Click here to see answer by richard1234(5390)
 Question 389241: one x-intercept for a parabola is at the point (0.6,0)use the quadratic formula to find the other x-intercept for the parabola defined by the equation: y=-5x^2+8x-3. Click here to see answer by ewatrrr(10682)

 Question 389246: Find the x-intercepts defined by the equation: y=3x^2+3x-6. Click here to see answer by ewatrrr(10682)

 Question 389254: Find the x-intercepts for the parabola defined by the equation: y=-2x^2-4x+6. Click here to see answer by ewatrrr(10682)

 Question 389258: one x-intercept for a parabola is at the point (3,0).Use the quadratic formula to find the other x-intercept for the parabola defined by the equation: y= x^2-2x-3. Click here to see answer by CharlesG2(828)

 Question 389251: one x-intercept of a parabola is at a point of (1,0)use the factor method to find the other x-intercept defined by this equation: y=-5x^2+15x-10. Click here to see answer by ewatrrr(10682)

 Question 389266: Find the x-intercepts of the parabola with vertex (-1,-108)and y- intercepts (0,-105). Click here to see answer by Fombitz(13828)

 Question 389288: how do you graph this hyperbola : (x-1)^2-9(y-4)^2=36 Click here to see answer by Fombitz(13828)

 Question 389425: Find the x-intercepts of the parabola with vertex (4,-1)and y- intercept (0,15). Click here to see answer by ewatrrr(10682)

 Question 389427: Find the x-intercepts of the parabola with vertex (-5,80) and y-intercept (0,-45). Click here to see answer by ewatrrr(10682)

 Question 389516: It asks for the standard form of the equation of this conic: 4x^2 - 5y^2 - 16x - 30y - 9 = 0 I know the standard form is going to be the form of a hyperbola, since a and c are not equal and have opposite signs. I also know that completing the square is part of solving this too, I just don't really know how to apply it to a conic. Help is much appreciated! Click here to see answer by haileytucki(390)

 Question 389589: Find the X-intercept of the parabola with vertex (-1,-108) and y-intercept of (0,-105). Click here to see answer by ewatrrr(10682)
 Question 389589: Find the X-intercept of the parabola with vertex (-1,-108) and y-intercept of (0,-105). Click here to see answer by Edwin McCravy(8909)