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Tutors Answer Your Questions about Quadratic-relations-and-conic-sections (FREE)
Question 248303: Find the coordinates of the center and the radius of each circle whose equation is given. Then draw the graph.
#31)
I am confused about what to do after expanding the y^2+6y part to (y+6y+9)^2. The "-14x" is also confusing me.
Any help would be greatly appreciated!
Click here to see answer by stanbon(57977) |
Question 250320: I need help on this program complete the square, then graph conic section
x^2+y^2+4x+6y-3=0
So far I have x^2+y^2+4x+6y=-3
(x^2+4x)+y^2+6y=-3
I'm confused at this point
When you do get it in this form (x-h)^2+(y-k) how do you go about graphing it?
Click here to see answer by richwmiller(9144)  |
Question 251076: Three tracking stations have detected a earthquake in the local area. The fist stations is located at the origin ion the county map, where each unit of the grid represents one square mile. The second and third stations are located at (8, -8) and (11, 10), respectively. The epicenter of th4e earthquake is 5 miles from the first tracking station, 13 miles from the second tracking station, and 10 miles from the third tracking station. What are the coordinated of the epicenter of the earthquake? Explain your answer.
Click here to see answer by solver91311(17077)  |
Question 251077: Two condominium apartment buildings that face each other have a front door awning that is shaped like a hyperbola. The equation of the hyperbola is 25x^2 - 81y^2 = 30,625. Find the distance in meters between the two front door awnings at their closest point.
Click here to see answer by jsmallt9(3296) |
Question 251131: 1. y= -3x^2 - 18x + 5
equation in (h,k) form:
Vertex:
Direction of opening:
2.9x^2-16y^2-32y+128=0
equation in (h,k) form:
Vertex:
Direction of opening:
3. Solve system using substitution or elimination. Give real and non-real coordinate solutions.
3x^2-y^2=9
x^2+4y^2=3
Click here to see answer by nyc_function(2733)  |
Question 253258: Need to turn this into standard form...
4x^2+4y^2-24+16y-100=0
4x^2+4y^2+16y=124
4x^2+4y^2+16Y+(1/2 of 16 =8^2=64)=124
4x^2 +4y^2+16y+64-64=124-64
4x^2 + 4y^2+16y=64
4x^2+ (2y+4)^2=64 or 8^2
I know this is not right but i do not know what to do.
Click here to see answer by jim_thompson5910(28717) |
Question 253258: Need to turn this into standard form...
4x^2+4y^2-24+16y-100=0
4x^2+4y^2+16y=124
4x^2+4y^2+16Y+(1/2 of 16 =8^2=64)=124
4x^2 +4y^2+16y+64-64=124-64
4x^2 + 4y^2+16y=64
4x^2+ (2y+4)^2=64 or 8^2
I know this is not right but i do not know what to do.
Click here to see answer by Edwin McCravy(8999)  |
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