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Tutors Answer Your Questions about Quadratic-relations-and-conic-sections (FREE)
Question 229242: Hello. I'm working on a question in Algebra 2 in quadratics. It says:
A store charges $2 for a one-day rental of a video cassette. On the average, 200 cassettes are rented from the store each day. If a survey indicates that the store's rentals will decrease by and average of 5 per day for each 10-cent increase in rental charge, what should the store charge to maximize its income?
I figured out that charging $2 and $4 was the same profit ($400 a day), so that means the answer is $3, but I need to show my work in a h(t)=-.5gt+vt+h, where V and H are sub 0. How does this problem fit into that formula?
Click here to see answer by ankor@dixie-net.com(6693)   |
Question 229242: Hello. I'm working on a question in Algebra 2 in quadratics. It says:
A store charges $2 for a one-day rental of a video cassette. On the average, 200 cassettes are rented from the store each day. If a survey indicates that the store's rentals will decrease by and average of 5 per day for each 10-cent increase in rental charge, what should the store charge to maximize its income?
I figured out that charging $2 and $4 was the same profit ($400 a day), so that means the answer is $3, but I need to show my work in a h(t)=-.5gt+vt+h, where V and H are sub 0. How does this problem fit into that formula?
Click here to see answer by cornball3440(10)  |
Question 229396: i am trying to find the y coordinate of the vertex. the x is -2 and when i plug it in to the equation i get
3(-2)^2+12(-2)+8 =-28, but the answer is supposed to be -4 can someone tell me what i am doing wrong?
Click here to see answer by rfer(2688) |
Question 233345: Hello. I am having a question in the CPM Algebra 2 book on pg.179. My chapter, that I am on, is about parabola equations. You can find the problem and any diagrams on hotmath.com. The question is this...
4-47
"A jackrabbit is jumping over a three-foot-high fence. To clear the fence, the rabbit must start its jump at a point four feet from the fence and will end four feet from the fence"
When drawing this graph and making an equation, I am unsure where to go about this problem, to write this equation. Please help. Much appreciated:)
Click here to see answer by Theo(675)  |
Question 235864: x^2-4x-21=0
we must find Δ in oder to know in which conditions this equation must be solved.
Δ=((-b)^2-4*a*c)
(*)if Δ>0 this equation has 2 solutions x=(-bą√Δ)/2a.
(**)if Δ=0 this equation has only one solution x=-b/2a.
(***)if Δ<0 this equation must be solved by a transformation of Δ to a complex number.
if we apply Δ's formula:
Δ=(-(-4))^2-4*(-21)=100 then Δ>0 so we must refered to condition(*)in oder to solve this equation.
√Δ=10
this equation has 2 results x1,x2.
x1=(-(-4)-10)/2; x2=(-(-4)+10)/2
x1=-3;x2=7
S={-3;7}
Click here to see answer by checkley77(7072) |
Question 235864: x^2-4x-21=0
we must find Δ in oder to know in which conditions this equation must be solved.
Δ=((-b)^2-4*a*c)
(*)if Δ>0 this equation has 2 solutions x=(-bą√Δ)/2a.
(**)if Δ=0 this equation has only one solution x=-b/2a.
(***)if Δ<0 this equation must be solved by a transformation of Δ to a complex number.
if we apply Δ's formula:
Δ=(-(-4))^2-4*(-21)=100 then Δ>0 so we must refered to condition(*)in oder to solve this equation.
√Δ=10
this equation has 2 results x1,x2.
x1=(-(-4)-10)/2; x2=(-(-4)+10)/2
x1=-3;x2=7
S={-3;7}
Click here to see answer by cheikoda(2) |
Question 237858: Okay, so what is a eauation for a line of symmetry for (x-2)(x-2)
also what are you equations for parabolas, with (2,0) as a vertex.
anyways i dont want you tto tell me the anwer i wannt to know how to answer, so it will help me
thanks :D
Click here to see answer by solver91311(5072)  |
Question 237815: I am given the length, and height of a parabola which is positioned like a bridge, therefore the parabola's opening is downwards. The Length of the base of the parabola is 5meters, the height is 4meters. I need to find the maximum height of a rectangle to fit into the parabola(bridge). The rectangle cannot be the height of the parabola, and the edges cannot go past the parabola. The Width of the rectangle is 2meters. What is the maximum height of the rectangle so that it would fit through the parabola, without getting stuck? How would you write the equation of the parabola? Would it be y= -a(x-4)^2+0 ?? Is the vertex (0,4) ?
Click here to see answer by ankor@dixie-net.com(6693) |
Question 239721: Identify the coordinates of the vertex, and focus, the equations of the axis of symmetry and directirix, and the directions of opening of the parabola with the given equation. Then find the length of the latus rectum and graph the parabola.
-2(y-4)=(x-1)^2
I'm confused on each part, in general. Can you help me on each step?
Click here to see answer by stanbon(26291) |
Question 240467: I'm in dire need of help on my Honors pre-calculus assignment.
I'm given the foci (3,+-2) and the x intercepts of -1 and 7 .
How do I find the equation of the conic (parabola, hyperbola, or ellipse) described?
Click here to see answer by scott8148(3382)  |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395
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