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Tutors Answer Your Questions about Quadratic-relations-and-conic-sections (FREE)
Question 190691: determine whether the following equations represent a parabola, circle, ellipse or hyperbola
4x^2 + 6y^2 - 4x - 9y + 12 = 0
3x^2 + 2x - 5y + 12 = 0
4x^2 + 4y^2 -4x + 9y + 1 = 0
9x^2 + 12 y^2 + 4x + 4y + 4 = 0
5x^2 - 2y^2 + 2x - 6y - 6 = 0
How do I determine this?
Click here to see answer by Alan3354(31538)  |
Question 192364: I am being asked to graph:
4x^2-y^2>36
So i know that it is going to be a hyperbola, but how can i get it into a neat standard form? Am i supposed to divide by 36 on both sides and deal with the messy X term, or is there a different way?
Click here to see answer by Mathtut(3670) |
Question 192360: I am being asked to graph:
4x^2-y^2>36
So i know that it is going to be a hyperbola, but how can i get it into a neat standard form? Am i supposed to divide by 36 on both sides and deal with the messy X term, or is there a different way?
Click here to see answer by Mathtut(3670) |
Question 192403: Please help me with this.
The directions say to Find is foci.
Today in class we learned that the foci meant the same term as focus.
I have been struggling with this problem.
This what I have tried so far.
I tried dividing everything by one therefore I would get

a=9
b=1
c=
However it just isn't working out so I do not know if I have making a small mistake.
Click here to see answer by stanbon(57984) |
Question 192405: Please help me with this.
The directions say to Find is foci.
Today in class we learned that the foci meant the same term as focus.
I have been struggling with this problem. We are dealing with graphing and working with conic sections: ellipses and hyperbolas.
This what I have tried so far.
I tried dividing everything by one therefore I would get

a=9
b=1
c=
However it just isn't working out so I do not know if I have making a small mistake.
Click here to see answer by Mathtut(3670) |
Question 192645: I do not understand how to solve this problem:
Write the equation of the parabola with vertex (-2,-2) and directrix y=0.
I know that the form should be y=a(x-k)^2+k
and that it should be a(x+2)^2-2
but I don't get how to get the a.
Answer to problem is: -(1/8)(x+2)^2-2
Click here to see answer by stanbon(57984) |
Question 193376: Find the vertex, focus, directrix, and axis of symmetry of each parabola.
We have been using the formulas y-k=a(x-h)^2 and x-h=a(y-k)^2 I don't understand which to use here, even after completing the square and its confusing because I don't know which is which. please explain and be specific. thank you.
Click here to see answer by solver91311(17077)  |
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