SOLUTION: for the parabola : y = -x^2 + 36. Graph of a parabola opening down at the vertex (0,36) crossing the x�axis at (-6,0) and (6,0).

SOLUTION: for the parabola : y = -x^2 + 36. Graph of a parabola opening down at the vertex (0,36) crossing the x�axis at (-6,0) and (6,0).

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Question 993785: for the parabola : y = -x^2 + 36.
Graph of a parabola opening down at the vertex (0,36) crossing the x�axis at (-6,0) and (6,0).
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

John

My calculator said it, I believe it, that settles it

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