SOLUTION: How do you find the focus and directrix of the parabola y=x^2-4x+4 and graph it?

Algebra.Com
Question 985894: How do you find the focus and directrix of the parabola y=x^2-4x+4 and graph it?
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
first write your equation in vertex form : where and are and coordinates of the vertex
......complete square; here you have
=> , and
vertex is at:(,)
=> parabola opens upwards
then the focal distance , in this case and
focus | (, )
semi-axis length |
directrix |


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