SOLUTION: Find an equation in standard form for the hyperbola with vertices at (0, �10) and asymptotes at y = � 5/4 x Here is my work, I would just like to double check my work: y= +/

Question 982288: Find an equation in standard form for the hyperbola with vertices at (0, �10) and asymptotes at
y = � 5/4 x
Here is my work, I would just like to double check my work:
y= +/- (b/a)x
x^2/a^2- y^2/b^2 = 1
x^2/16 - y^2/25 =1

Thank you in advance!
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Close, but no cigar. For a hyperbola centered at the origin, the vertices are at (0,-a) and (0,a). You were correct to say that a and b are in the ratio 5/4 because of the slopes of the asymptote equations, but you left off the step where you should have calculated the correct value of b based on the fact that a = 10 because of the specification of the vertices.

Solve for b and give your equation another try.

John

My calculator said it, I believe it, that settles it

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