SOLUTION: Identify the vertices of the hyperbola (x + 4)^2/9 - (y -1)^2/16 = 1. I think the center is (-4,1) but I don't remember how to find vertices

Question 979287: Identify the vertices of the hyperbola
(x + 4)^2/9 - (y -1)^2/16 = 1.
I think the center is (-4,1) but I don't remember how to find vertices
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The x^2 term is positive, so the hyperbola opens in the horizontal direction (along the x axis). That means we add and subtract 3 from the x coordinate of the center to get the vertices. Why 3? Because a^2 = 9 means a = 3.

(-4,1) ---> (-4+3,1) = (-1,1) is one vertex

(-4,1) ---> (-4-3,1) = (-7,1) is the other vertex
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