SOLUTION: A parabola has an x intercept at 2, its axis symmetry is the line x=4 and the y coordinate of its vertex is 6. Determine the equation of the parabola. How do I begin to solve this?

Question 978623: A parabola has an x intercept at 2, its axis symmetry is the line x=4 and the y coordinate of its vertex is 6. Determine the equation of the parabola. How do I begin to solve this? There is a hint y-r=a(x-t)^2. Not sure how to use that.
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Almost. Use one more term, although shown with different variables:
.

The vertex is (4,6) which corresponds to (h,k). The given x-intercept is (2,0) and because of symmetry, the other is (6,0). So far you have enough to know .

Solve for a, and then substitute either coordinate values for either x-intercept...
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