SOLUTION: My question is how to I put h(x)=4x^2+3x+6 in standard form. I can't complete the square unless the coefficient of the x^2 is a one. I can't pull out anything. How would I go about
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Question 978043: My question is how to I put h(x)=4x^2+3x+6 in standard form. I can't complete the square unless the coefficient of the x^2 is a one. I can't pull out anything. How would I go about this problem? Thanks in advance.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ =\ 4x^2\ +\ 3x\ +\ 6)
\ =\ 4\left(x^2\ +\ \frac{3}{4}x\right)\ +\ 6)
\ =\ 4\left(x^2\ +\ \frac{3}{4}x\ +\ \left(\frac{3}{8}\right)^2\right)\ +\ 6\ -\ 4\left(\frac{3}{8}\right)^2)
You should be able to factor the perfect square trinomial and do the clean up arithmetic yourself.
John
My calculator said it, I believe it, that settles it
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