SOLUTION: Find the vertices and the foci of the ellipse with the given equation. Then draw the graph. 25x^2+16y^2=1

Question 960769: Find the vertices and the foci of the ellipse with the given equation. Then draw the graph. 25x^2+16y^2=1
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the vertices and the foci of the ellipse with the given equation. Then draw the graph. 25x^2+16y^2=1
***
given ellipse has a vertical major axis
Its standard form of equation:
For given ellipse:

center: (0,0)
a^2=1/16
a=1/4
b^2=1/25
b=1/5
vertices: (0,�a)=(0, 0�(1/4))=(0, -(1/4)) and (0, (1/4)
c^2=a^2-b^2=1/16-1/25=25/400-16/400=9/400
c=3/20
foci: (0,�c)=(0, 0�(3/20))=(0, -(3/20)) and (0, (3/20)
..
y=.25(1-25x^2)^.5
see graph below:

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