SOLUTION: (x-5)^2 /4+ (y+3)^2 /16=1
How do you find the major and minor axis
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Question 936070: (x-5)^2 /4+ (y+3)^2 /16=1
How do you find the major and minor axis
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
(x-5)^2 /4+ (y+3)^2 /16=1
How do you find the major and minor axis
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1/2 is the sqrt of the divisors.
sqrt(4) = 2
sqrt(16) = 4
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4 is larger --> semi-major
--> major = 8
--> minor = 4
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