SOLUTION: How do I find the latus rectum of (x-1)^2=-8(y+1) Thank You

Question 929975: How do I find the latus rectum of (x-1)^2=-8(y+1)
Thank You

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
the vertex form of a Parabola opening up(a>0) or down(a<0),

where(h,k) is the vertex and x = h is the Line of Symmetry ,
the focus is (h,k + p), With Directrix y = (k - p), a = 1/(4p)
.........
(x-1)^2 =-8(y+1)
y = (-1/8)(x-1)^2 -1
1/(4p) = -1/8, p = -2
latus rectum 8units in length (horizontal blue LINE segment thru the focus)

RELATED QUESTIONS
How do I find the vertex, focus, directrix, axis of symmetry, and latus rectum of this... (answered by Edwin McCravy)

I am trying to get ahead on my homework. How do you find the focus point of y^(2)=(8/3)x? (answered by lwsshak3)

Identify vertex, focus, directrix, axis of symmetry and latus rectum from the following... (answered by Edwin McCravy)

Find the foci, eccentricity, length of latus rectum, and the x and y intercepts of the... (answered by MathLover1)

How do you find the equation, vertex, focus, directrix, and latus rectum of the... (answered by lwsshak3)

Given the equation of the parabola (x+2)^2=2(y-1), find the vertex, directrix, focus and... (answered by josgarithmetic)

Find the coordinates of the foci, the endpoints of the major axis, minor axis and the... (answered by MathLover1)

Find the equation of the parabola with latus rectum 6 joining ( -4, 1) and (2,... (answered by MathLover1)