SOLUTION: Find the equation for a hyperbola with eccentricity 3/2 and directrix x=2

Algebra.Com
Question 927600: Find the equation for a hyperbola with eccentricity 3/2 and directrix x=2
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
The easiest hyperbola with directrix x=2 and eccentricity 3/2
is found by taking the focus to be the origin.



We take an arbitrary point (x,y) on the hyperbola, and, (in blue)
draw one line from the arbitrary point (x,y) to the focus (0,0) and
another line directly to and perpendicular to the directrix x=2

The ratio of the two blue lines is equal to the eccentricity 3/2.

The horizontal blue line has length |2-x|,

The slanted blue line has length  or


So we set their ratio equal to 3/2

 

Square both sides













Edwin


RELATED QUESTIONS

a hyperbola of eccentricity 3/2 has one focus at (1,-3). The corresponding directrix is... (answered by Edwin McCravy)
Find a polar equation of a hyperbola with its focus at the pole, an eccentricity of e... (answered by MathLover1)
Find the equation of the hyperbola for each given conditions. d. Focus at (4,0) and... (answered by MathLover1)
Find a polar equation of a hyperbola with its focus at the pole, an eccentricity of e... (answered by MathLover1)
Find the equation in standard form of a hyperbola with vertices (1,-3) and (-5,-3 and... (answered by lwsshak3)
The vertices of a hyperbola are the points (−3, 2) and (−3, −2) and the length of... (answered by ikleyn)
write the equation of conic with eccentricity e,focus(a,0) and directrix y-axis... (answered by fractalier)
Find the equation of the hyperbola having foci at(4,2)and (8,2) and eccentricity (e) is... (answered by MathLover1)
The standard form equation for a parabola with focus (2, –3) and directrix x = 5... (answered by lwsshak3)