SOLUTION: how to graph: x^2+4y^2+4x-8y-8

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Question 920593: how to graph: x^2+4y^2+4x-8y-8
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
x^2+4y^2+4x-8y-8 = 0
(x-2)^2-4 + 4(y-1)^2 -4 -8 = 0
(x-2)^2 + 4(y-1)^2 = 16
(x-2)^2/16 + (y-1)^2/4 = 1 Ellipse C(2,1) major axis along y = 1
Standard Form of an Equation of an Ellipse is



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