SOLUTION: What are (a) the x-intercepts, (b) the y-intercepts and (c) the foci of the following ellipse? (leave answers exact; do not round) x^/25 + y^2/36=1 I need help with all three

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What are (a) the x-intercepts, (b) the y-intercepts and (c) the foci of the following ellipse? (leave answers exact; do not round) x^/25 + y^2/36=1 I need help with all three      Log On


   



Question 920283: What are (a) the x-intercepts, (b) the y-intercepts and (c) the foci of the following ellipse? (leave answers exact; do not round)
x^/25 + y^2/36=1
I need help with all three (a) (b) and (c). thank you.

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
x^2/25+y^2/36=1
x^2/(5)^2 + y^2(6)^2=1
36 is bigger than 25, a^2 term is the denominator of y^2 term, and b^2 term is the denominator of x^2 term.
This is an ellipse & major axis is vertical.
h,k = (0,0)

Center:(0,0)
a=6
b=5
----------------------
(c) Foci
c^2=a^2+b^2=6+5=11
c=√11
Foci:(0,0±√11)
-------------
(a) x-intercept
y=0
x^2/25=1
x^2=25
x=±5
-------------
(b) y-intercept
x=0
y^2/36=1
y^2=36
y=±6
----------------

x-intercept:±5
y-intercept:±6
Foci:(0,0±sqrt%2811%29)