SOLUTION: Graph the following conic section x=y^2+6y+5

Question 917613: Graph the following conic section
x=y^2+6y+5
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Graph the following conic section
x=y^2+6y+5
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Not a function, so cannot be shown on this site.
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Parabola opening to the right from its vertex.
Vertex occurs at y = -b/(2a) = -6/(2) = -3
x = 9-18+5 = -4
Vertex(-4,-3)
x-intercept:: (5,0)
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Cheers,
Stan H.
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