SOLUTION: a circle touches the circle (x+1)^2+y^2=9 and passes through (1,0). find the locus of its center. PLEASE GIVE SOLUTION (ANSWER: 20x^2+36y^2=45).thx XD

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Question 912053: a circle touches the circle (x+1)^2+y^2=9 and passes through (1,0). find the locus of its center. PLEASE GIVE SOLUTION (ANSWER: 20x^2+36y^2=45).thx XD
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
a circle touches the circle (x+1)^2+y^2=9 and passes through (1,0). find the locus of its center. PLEASE GIVE SOLUTION (ANSWER: 20x^2+36y^2=45).thx XD
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Do you mean it's tangent to the circle?
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(1,0) is inside the given circle, so the circles will be internally tangent.
The radius of (x+1)^2+y^2=9 is 3.
The center of the circles is (h,k)
The distance from (h,k) to (1,0) =
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The distance also equals 3 - [the distance from (h,k) to (-1,0)]
=
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Sub x & y for (h,k)


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