SOLUTION: I need to know the vertex, axis of symmetry, roots, domain, range for the following problem Y=2(x+2)^2-5 i also need to know if it opens up or down and if you can graph it that w

Question 911616: I need to know the vertex, axis of symmetry, roots, domain, range for the following problem
Y=2(x+2)^2-5
i also need to know if it opens up or down and if you can graph it that would be greatly appreciated.
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
It's in vertex form.
(-2,-5) is the vertex.
The axis of symmetry is .
Domain is all real x values, (,).
Since , the parabola opens upwards and the vertex value is the minimum.
The range is [,).
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Need to Know: the vertex form of a Parabola opening up(a>0) or down(a<0):
where(h,k) is the vertex and x = h is the Line of Symmetry
Y= (x+2)^2-5
Upward a = 2 > 0
V(-2,-5), axis of symmetry: x = -2

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