SOLUTION: I need to know the Vertex, Axis of Symmetry, roots, domain, and the range for the following problem.
Y=x^2-4
I also need to know if it opens up or down and if you could graph it
Algebra.Com
Question 910369: I need to know the Vertex, Axis of Symmetry, roots, domain, and the range for the following problem.
Y=x^2-4
I also need to know if it opens up or down and if you could graph it that would be greatly appreciated.
Found 2 solutions by richwmiller, ewatrrr:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Duplicate or similar
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
recommend the free graphing software download:
https://www.padowan.dk/download/
Algebraically
y = x^2 - 4 = = (x+2)(x-2) roots: -2,2
........
the vertex form of a Parabola opening up(a>0) or down(a<0),
where(h,k) is the vertex and x = h is the Line of Symmetry
.......
y = x^2 - 4 V(0,-4), Axis of Symmetry x = 0, a= 1> 0 Opens Upward
domain: All real Numbers
range [-4, ∞ )
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