SOLUTION: Find the vertex, focus, and directix of the parabola (x+2)^2 = 8(y-3)

Question 893760: Find the vertex, focus, and directix of the parabola
(x+2)^2 = 8(y-3)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the vertex, focus, and directrix of the parabola
(x+2)^2 = 8(y-3)
***
This is an equation of parabola that opens upwards:
Its basic form of equation: (x-h)^2=4p(y-k)^2, (h,k)=coordinates of vertex
For given problem:
vertex:(-2,3)
axis of symmetry: x=-2
4p=8
p=2
focus: (-2,5) (p-units above vertex on the axis of symmetry)
directrix: y=1 (p-units below vertex on the axis of symmetry)
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