SOLUTION: find the vertices and foci of the ellipse 3x^2+4y^2=12

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Question 893103: find the vertices and foci of the ellipse
3x^2+4y^2=12

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
find the vertices and foci of the ellipse
3x^2+4y^2=12
x%5E2%2F4%2By%5E2%2F3=1
This is an equation of an ellipse with horizontal major axis and center at the origin
Its standard form of equation: x%5E2%2Fa%5E2%2By%5E2%2Fb%5E2=1
center:(0,0)
a^2=4
a=2
vertices: (0±a,0)=(0±2,0)+(-2,0) and (2,0)
..
b^2=3
c^2=a^2-b^2=4-3=1
c=1
foci: (0±c,0)=(0±1,0)+(-1,0) and (1,0)