SOLUTION: the equation of tangent at a point (5,1) to the circle x^2+y^2-2x+4y-20=0 will be???

SOLUTION: the equation of tangent at a point (5,1) to the circle x^2+y^2-2x+4y-20=0 will be???

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Question 884621: the equation of tangent at a point (5,1) to the circle x^2+y^2-2x+4y-20=0 will be???
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Find the value of the derivative at the point.
The derivative is equal to the slope of the tangent line.
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At (5,1),

Using the point slopt form of a line,

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