SOLUTION: Identify the vertex, focus, and Directrix of the graph of this parabola: (x-1)^2 = (1/4)(y+2)

Question 879415: Identify the vertex, focus, and Directrix of the graph of this parabola:
(x-1)^2 = (1/4)(y+2)
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
(x-1)^2 = (1/4)(y+2) Opening Upward along x = 1
C(1,-2), 4p = 1/4, p = 1/16, F(1, -1 15/16), Directrix is y = -2 1/16)

 

Hi

Need to Know...............................................................

Standard Form of an Equation of a Circle is  

Standard Form of an Equation of an Ellipse is  

Standard Form of an Equation of an Hyperbola opening up and down is: 

Standard Form of an Equation of an Hyperbola opening right and  left is: 

the vertex form of a Parabola opening up(a>0) or down(a<0), 

 the vertex form of a Parabola opening right(a>0) or left(a<0), 



 

RELATED QUESTIONS

Identify the vertex, focus, and directrix of the parabola.... (answered by stanbon)
Identify the vertex, focus, and directrix of the parabola. x=-1/4(y+1)^2+2 Thanks  (answered by lwsshak3)
how do you identify the vertex, focus, and directrix of the parabola
y=x^2+4x+3
And... (answered by stanbon)
identify the vertex, focus, and directrix of the problem.... (answered by stanbon)
Find the vertex, focus, directrix, and focal width of the parabola. Show the graph.
{{{... (answered by MathLover1)
identify the vertex and focus of this parabola:
y-4=1/16(x-2)^... (answered by lwsshak3)
Identify the vertex, focus, and directrix of the graph of... (answered by lwsshak3)
Identify the vertex and directrix of the parabola (x+4)^2=-1/8(y+3)

and

Write the... (answered by lwsshak3)
Find the vertex, focus, and directrix of the parabola.... (answered by lwsshak3,TimothyLamb)