SOLUTION: Find the center, and the lengths of the transverse and conjugate axes of the hyperbola.Get the equation into standard form for a hyperbola.
Find the center, and the lengths of the
Algebra.Com
Question 876473: Find the center, and the lengths of the transverse and conjugate axes of the hyperbola.Get the equation into standard form for a hyperbola.
Find the center, and the lengths of the transverse and conjugate axes.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the center, and the lengths of the transverse and conjugate axes.z
***
9x^2+ 126x - 16y^2 + 288y - 999 = 0
complete the square:
9(x^2+ 14x +49) - 16(y^2 - 18y + 81) = 999+441-1296
9(x+7)^2-16(y-9)^2=144
This is an equation of a hyperbola with horizontal transverse axis.
Its standard form of equation: , (h,k)=coordinates of center
For given hyperbola:
center: (-7, 9)
a^2=16
a=4
length of transverse axis=2a=8
b^2=9
b=3
length of conjugate axis=2b=6
RELATED QUESTIONS
find the eccentricity of a hyperbola whose transverse and conjugate axes are equal in... (answered by addingup)
What are the lengths of the transverse and conjugate axes of the hyperbola given by the... (answered by lwsshak3)
The equation of a hyperbola is given by y^2/25 - (x-6)^2/144 = 1.
a. Identify the... (answered by lwsshak3)
If length of transverse axis is 8 and conjugate axis is 10 and transverse axis is along... (answered by ikleyn)
2. The equation of a hyperbola is given by (x-1)^2/16 - (y+1)^2/9 =1
a. Give the... (answered by ewatrrr)
Use the following hyperbola to answer all questions.
Find the center, foci, vertices,... (answered by Edwin McCravy)
May you please help me with the following hyperbola in standard form:
{{{(1/10)(x-1)^2 (answered by Edwin McCravy)
Find an equation for a hyperbola centered at the origin with a horizontal transverse axis (answered by ewatrrr)