SOLUTION: Determine the coordinates of the focus of the parabola y= 1/16 x2 Be sure to write your answer as an ordered pair.

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Question 876025: Determine the coordinates of the focus of the parabola y= 1/16 x2
Be sure to write your answer as an ordered pair.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
y= (1/16) x^2 Opens Upward along x = 0
V(0,0)
1/16 = 1/(4p) = 1/16, p = 4
F(0,4)
the vertex form of a Parabola opening up(a>0) or down(a<0), y=a%28x-h%29%5E2+%2Bk
where(h,k) is the vertex and x = h is the Line of Symmetry
The standard form is %28x+-h%29%5E2+=+4p%28y+-k%29, 0r a = 1/4p, where the focus is (h,k + p)
With Directrix y = (k - p)