SOLUTION: (x-4)^2/49+(y+5)^2/16=1 Find the center, the major axis, the minor axis, and the distance from the center to the foci

Question 875578: (x-4)^2/49+(y+5)^2/16=1
Find the center, the major axis, the minor axis, and the distance from the center to the foci
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
(x-4)^2/49+(y+5)^2/16=1
Find the center, the major axis, the minor axis, and the distance from the center to the foci
***
Given equation is that of an ellipse with horizontal major axis.
Its standard form of equation: ,a>b, (h,k)=coordinates of center.
center: (4,-5)
a^2=49
a=7
length of major axis=2a=14
b^2+16
b=4
length of minor axis=2b=8
c^2=a^2-b^2=49-16=33
c=√33
distance from the center to the foci=√33-4≈1.74

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