SOLUTION: find the center, foci, asymptotes and a graph the hyperbola in the space provided: (x-2)^2/36 -(y-3)^2/25 =1 Please Help with this. I really need it. Thank you!

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Question 875386: find the center, foci, asymptotes and a graph the hyperbola in the space provided:
(x-2)^2/36 -(y-3)^2/25 =1
Please Help with this. I really need it. Thank you!

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
Standard Form of an Equation of an Hyperbola opening right and left is:
with C(h,k) and vertices 'a' units right and left of center,
Foci are = c- units right and left of center along y = k
& Asymptotes Lines passing thru C(h,k), with slopes m = ± b/a
(x-2)^2/36 -(y-3)^2/25 =1 Opening right and Left along y = 3
center: (2,3)
foci: c = sqrt(36+25) = sqrt(61), F(2+√61,3) and F(2-√61, 3)
asymptotes: m = ± b/a = ± 5/6
y - 3 = 5/6(x-2), y = (5/6)x + 4/3
y - 3 = -5/6(x-2), y = (-5/6)x + 14/3


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