SOLUTION: Find the vertex and focus of the parabola : y^2 + 4y + 8x -12=0

SOLUTION: Find the vertex and focus of the parabola : y^2 + 4y + 8x -12=0

Algebra.Com

Question 874400: Find the vertex and focus of the parabola : y^2 + 4y + 8x -12=0

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
y^2 + 4y + 8x -12=0
(y + 2)^2 - 4 + 8x -12 = 0
(y+2)^2 = -8x + 16 V(
(y+2)^2 = -8(x-2) V(2, -2) Opening left along y = -2
4p = -8, p = -2, F(0,-2)
RELATED QUESTIONS
Find the vertex, focus, and directrix of the parabola.... (answered by lwsshak3)

Find the vertex and focus of the parabola... (answered by lwsshak3)

Find the vertex and focus of the parabola... (answered by josgarithmetic)

x^2+8x-y+6=0 Find the vertex, focus, and directrix of the parabola. Sketch the... (answered by Nate)

Give the vertex, focus, directrix, and the distance across parabola at focus, and then... (answered by Edwin McCravy,nerdybill)

Find the vertex and focus of the parabola. X^2 - 4y^2 = 0 (answered by josgarithmetic)

parabola,x^2 +6x -y +11 =0 find the vertex,focus and directrix of the... (answered by lwsshak3)

What is the vertex, axis of symmetry, focus, and directrix of the parabola... (answered by MathLover1)

Find the vertex, focus, and directrix of the parabola. Graph the equation. y^2 - 2y =... (answered by lwsshak3)