SOLUTION: what are the vertex and axis of symmetry of the parabola y=x^2-16x+63

SOLUTION: what are the vertex and axis of symmetry of the parabola y=x^2-16x+63

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Question 873062: what are the vertex and axis of symmetry of the parabola y=x^2-16x+63
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
y=x^2-16x+63
y=(x-8)^2 - 64 + 63
y=(x-8)^2 - 1, V(8,-1) axis of symmetry x = 8
Opening Upward: a = 1 > 0
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