SOLUTION: (y+1)^2=-8(x+3)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: (y+1)^2=-8(x+3)      Log On


   

Question 870991: (y+1)^2=-8(x+3)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
(y+1)^2=-8(x+3)
This is and equation of a parabola that opens leftward.
Its basic form of equation: (y-k)^2=-4p(x-h)
For given parabola:
vertex:(-3,-1)
4p=8
p=2
focus: (-5,-1)
directrix: x=-1
What do you want to do with given problem?