SOLUTION: Let (ax+b)/(x^2-1)=a/(x+1)+b/(x-1). Find a and b. This is from the Pre-Cal Conics, rotation of axes section. Any help would be awesome. thank you

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Question 869890: Let (ax+b)/(x^2-1)=a/(x+1)+b/(x-1). Find a and b.
This is from the Pre-Cal Conics, rotation of axes section. Any help would be awesome. thank you
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
?
The right hand side,




Now, the numerators of left and right are the same. We started with the equality, so now just adjust numerators to same form and compare corresponding terms.





The way those correspond,
and
?



-
b=b-(a+b)
b=-a
One possibility is, a=0 and b=0.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Let (ax+b)/(x^2-1)=a/(x+1)+b/(x-1). Find a and b.
This is from the Pre-Cal Conics, rotation of axes section. Any help would be awesome. thank you 




ax + b = a(x - 1) + b(x + 1) ------ Multiplying by LCD, , or (x - 1)(x + 1)

ax + b = ax - a + bx + b

ax - ax + a = bx + b - b

, and  

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