SOLUTION: You and a friend are hiking in the mountains. You want to climb to a ledge that is 20 ft. above you. The height of the grappling hook you throw is given by the function h(t) = -16t

Question 868923: You and a friend are hiking in the mountains. You want to climb to a ledge that is 20 ft. above you. The height of the grappling hook you throw is given by the function h(t) = -16t^2 - 32t + 5.
What is the maximum height of the grappling hook? Can you throw it high enough to reach the ledge?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
You and a friend are hiking in the mountains. You want to climb to a ledge that is 20 ft. above you. The height of the grappling hook you throw is given by the function h(t) = -16t^2 - 32t + 5.
What is the maximum height of the grappling hook? Can you throw it high enough to reach the ledge?
***
h(t) = -16t^2 - 32t + 5.
complete the square:
h(t) = -16(t^2+2t+1)+16+ 5.
= -16(t+1)^2+21
This is an equation of a parabola that opens downward with vertex at (-1,21)csccs
maximum height of the grappling hook=21 ft
Yes, you can you throw it high enough to reach the ledge?
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