SOLUTION: How to change 16y^2-9x^2-576=0 to standard form?

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Question 866815: How to change 16y^2-9x^2-576=0 to standard form?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

16y^2-9x^2-576=0    |dividing thru by 576

y%5E2%2F36+-+x%5E2%2F64+=+1     

Note: y%5E2%2F6%5E2+-+x%5E2%2F8%5E2+=+1  Hyperbola Opening Up and Down along x = 0

 C(0,0) V(0,6) and V(0,-6), Foci: (0,10) and (0,-10)  |sqrt%2836%2B64%29| = 10