SOLUTION: I need to find the foci and the vertices of this hyperbola [(y+2)^2]/4-[x^2]/12=1 Please and thank you.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I need to find the foci and the vertices of this hyperbola [(y+2)^2]/4-[x^2]/12=1 Please and thank you.      Log On


   

Question 864753: I need to find the foci and the vertices of this hyperbola [(y+2)^2]/4-[x^2]/12=1
Please and thank you.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Standard Form of an Equation of an Hyperbola opening up and down is:

  %28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1 with C(h,k) and vertices 'b' units up and down from center

Foci sqrt%28a%5E2%2Bb%5E2%29units units up and down from center, along x = h

%28y%2B2%29%5E2%2F2%5E2+-x%5E2%2F12=1+  C(0,-2)

Vertices (0,0) and (0,-4)

Foci: sqrt(16) = 4 units Up and down from Center  (0, 2) and (0,-6)