SOLUTION: Sketch the graph of the quadratic equation x+y^2-cy=4, where c is a positive constant. Since y is squared and x is not, would it be a parabola that opens left/right? How do I f

Question 860380: Sketch the graph of the quadratic equation x+y^2-cy=4, where c is a positive constant.
Since y is squared and x is not, would it be a parabola that opens left/right?
How do I find the vertex and focus if it has a c?
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
The equation would be a parabola which opens left or right. Complete The Square for y and put the equation into standard form. x= something.

The term to use for completing the square is .

The axis of symmetry is horizontal, and will be on some line . The graph opens to the left. (The negative 1 coefficient says, "open to the left".) The farthest to the right that any points are for the graph is at . The vertex point is at , .

Note that c may be positive or negative or zero.
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