# SOLUTION: Find the vertex, focus, and directrix of the parabola given by each equation. Sketch the graph. 18. 3x+y^2+8y+4=0

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: Find the vertex, focus, and directrix of the parabola given by each equation. Sketch the graph. 18. 3x+y^2+8y+4=0      Log On

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 Question 85942This question is from textbook College Algebra : Find the vertex, focus, and directrix of the parabola given by each equation. Sketch the graph. 18. 3x+y^2+8y+4=0This question is from textbook College Algebra Answer by stanbon(57347)   (Show Source): You can put this solution on YOUR website!Find the vertex, focus, and directrix of the parabola given by each equation. Sketch the graph. 18. 3x+y^2+8y+4=0 Form: (y-k)^2=4p(x-h) y^2+8y+(8/2)^2 = -3x-4+(8/2)^2 (y+4)^2 = -3x+12 (y+4)^2 = -3(x-4) ---------- 4p=-3 p=-3/4 --------- Vertex at (h,k); (4,-4) focus at (h+p,k); (4-3/4,-4) = (11/4,-4) directrix:at x=h-p; x= 4-(-3/4)) = 19/4 ========= Cheers, Stan H.