SOLUTION: x^2-4x+4y-8=0 standard form
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Question 859201
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x^2-4x+4y-8=0 standard form
Answer by
ewatrrr(24785)
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Hi,
x^2-4x+4y-8=0
(x-2)^2 - 4 +4y - 8 = 0
4y = -(x-2)^2 +12
y = -.25(x-2)^2 + 3
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