Hi,

Please do NOT caps when posting.  So difficult to read.

 x^2 - 6x + y^2 + 4y + 9 = 0

(x-3)^2  + (y+2)^2 +9 = 0

 Circle:  C(3,-2),   r = 2 

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
 circle

center | (3, -2)

radius | 2

diameter | 4

area | 4 pi=12.5664

perimeter | 4 pi=12.5664

curvature | 1/2



(X-3)^2+(Y+2)^2=4  

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