SOLUTION: What is the equation of the tangent to a circle defined by the equation x^2+y^2-25=0 if the coordinates of the point of tangency are (-4,3)?

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Question 855249: What is the equation of the tangent to a circle defined by the equation x^2+y^2-25=0 if the coordinates of the point of tangency are (-4,3)?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
x^2+y^2 = 5^2 C(0,0) r = 5
( 0,0)
(-4,3) m = -3/4, slope of the radius drawn
Tangent Line: m = 4/3
***Using point-slope form, P(-4,3) point of tangency
y - 3 = 4/3(x + 4)
y = (4/3)x + 16/3 + 9/3
y = (4/3)x + 25 /3


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