SOLUTION: Graph the relation defined by the equation x^2+(y-3)^2 = 16 . Express the domain and the range of this relation in set-builder notation.
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Question 855247: Graph the relation defined by the equation x^2+(y-3)^2 = 16 . Express the domain and the range of this relation in set-builder notation.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Graph the relation defined by the equation x^2+(y-3)^2 = 16 . Express the domain and the range of this relation in set-builder notation.
x^2+(y-3)^2 = 16
This is an equation of a circle with center at (0,3) and radius=4
domain: {x|[-4,4]}
range: {y|[-1,7]}
see graph below:
y=(16-x^2)^.5+3
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