SOLUTION: determine the vertex, directrix, and the focus of (x+4)^2 + 4(y-1), (y-2)^2 = -2(x+3), (x-3)^2 = 8(y-4), (y+1)^2 + -4(x-1), and (x-2)^2 + 4(y-2) . and graph

Question 854409: determine the vertex, directrix, and the focus of (x+4)^2 + 4(y-1), (y-2)^2 = -2(x+3), (x-3)^2 = 8(y-4), (y+1)^2 + -4(x-1), and (x-2)^2 + 4(y-2) . and graph
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
determine the vertex, directrix, and the focus of
(x+4)^2 = 4(y-1)
vertex:: (-4,1)
4p = 4, so p = 1
Basic form: y = x^2(opens upward)
directrix: y = 1-p= 0
focus: (-4,1+p) = (-4,2)
-------------------------------
(y-2)^2 = -2(x+3)
vertex (-3,2)
Basic form: x = -y^2(opens to the left)
4p = -2, so p = -1/2
directrix: y = -3-p = -2.5
focus: (-3+p,2) = (-3.5,2)
=============================
Use the same procedure on the following:::
(x-3)^2 = 8(y-4), (y+1)^2 + -4(x-1), and (x-2)^2 + 4(y-2) .
=============
Cheers,
Stan H.
RELATED QUESTIONS
find the focus 1/4(x-2)^2=(y+3) and find the vertex and Directrix of -1/8(y+3)^2=(x-1) (answered by lwsshak3)

Identify the vertex, focus, and directrix of the parabola.... (answered by stanbon)

name the vertex, focus, and directrix of... (answered by lwsshak3)

what is the vertex, focus, and equation of directrix (y+3)^2 = -4(x-2) (answered by MathLover1)

Identify the vertex, focus, and Directrix of the graph of this parabola: (x-1)^2 =... (answered by ewatrrr)

Identify the vertex, focus, and directrix of the parabola. x=-1/4(y+1)^2+2 Thanks (answered by lwsshak3)

Find the vertex, focus and directrix of the parabola given by the equaiton (y + 2)^2 +... (answered by KMST)

(x-4)^2=8(y+3) whats its focus, vertex, and... (answered by josgarithmetic)

Find the vertx, the directrix, and the focus. (x-4)^2 =... (answered by crazylogms)