SOLUTION: Identify the center of the conic section whose equation is x 2 + y 2 + 6 x - 4 y - 12 = 0.
Algebra.Com
Question 853832: Identify the center of the conic section whose equation is x 2 + y 2 + 6 x - 4 y - 12 = 0.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Identify the center of the conic section whose equation is
x 2 + y 2 + 6 x - 4 y - 12 = 0.
x^2+6x+y^2-4y-12=0
complete the square:
(x^2+6x+9)+(y^2-4y+4)=12+9+4
(x+3)^2+(y-2)^2=25
This is an equation of a circle with center at (-3,2) and radius of 5
RELATED QUESTIONS
Identify the type of conic section whose equation is given and find the vertices and... (answered by Fombitz)
identify the conic section with the equation x^2 + y^2 - 6x - 4y - 68 = 0 (answered by scott8148)
find the standard form of each equation by completing the square then identify the conic... (answered by lwsshak3)
Identify the graph of the conic section defined by the following equation.... (answered by lwsshak3)
Identify the type of conic section that has the equation x^2+y^2=81. Identify the domain, (answered by richwmiller)
classify the conic section defined by thr equation. write the standard equation of the... (answered by jim_thompson5910)
Classify the conic section:
1. x2 + y2 = 36
2. x2 - y2 = 36
3. 5x2 +... (answered by Edwin McCravy)
Identify the conic section and write the standard form of the equation... (answered by scott8148)
Identify the conic section and write the standard form of the equation... (answered by scott8148)