SOLUTION: How do I write the standard equation of an ellipse with foci (4,2) and (-2,2) and eccentricity c/a=1/3.? Explain your solution completely

Question 852005: How do I write the standard equation of an ellipse with foci (4,2) and (-2,2) and eccentricity c/a=1/3.? Explain your solution completely
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
How do I write the standard equation of an ellipse with foci (4,2) and (-2,2) and eccentricity c/a=1/3.?
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Ellipse has a horizontal major axis.
Its standard form of equation: , a>b, (h.k)=center
x-coordinate of center=1 (midpoint between 4 and-2 on the major axis)
y-coordinate of center=2
center: (1,2)
c=3 (distance from center to foci on the major axis)
c^2=9
eccentricity=c/a=1/3
a=3c=9
a^2=81
c^2=a^2-b^2
b^2=a^2-c^2=81-9=72
Equation of given ellipse:

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